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12x^2-78x+126=0
a = 12; b = -78; c = +126;
Δ = b2-4ac
Δ = -782-4·12·126
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-78)-6}{2*12}=\frac{72}{24} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-78)+6}{2*12}=\frac{84}{24} =3+1/2 $
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